y=x^2+1+3x(x-3)-8(x+2)

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Solution for y=x^2+1+3x(x-3)-8(x+2) equation: 


Simplifying
y = x2 + 1 + 3x(x + -3) + -8(x + 2)

Reorder the terms:
y = x2 + 1 + 3x(-3 + x) + -8(x + 2)
y = x2 + 1 + (-3 * 3x + x * 3x) + -8(x + 2)
y = x2 + 1 + (-9x + 3x2) + -8(x + 2)

Reorder the terms:
y = x2 + 1 + -9x + 3x2 + -8(2 + x)
y = x2 + 1 + -9x + 3x2 + (2 * -8 + x * -8)
y = x2 + 1 + -9x + 3x2 + (-16 + -8x)

Reorder the terms:
y = 1 + -16 + -9x + -8x + x2 + 3x2

Combine like terms: 1 + -16 = -15
y = -15 + -9x + -8x + x2 + 3x2

Combine like terms: -9x + -8x = -17x
y = -15 + -17x + x2 + 3x2

Combine like terms: x2 + 3x2 = 4x2
y = -15 + -17x + 4x2

Solving
y = -15 + -17x + 4x2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Simplifying
y = -15 + -17x + 4x2

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